Page 97 - bingx

Contoh 2:
0
0
Hitunglah nilai dari 195 + 105 .
Penyelesaian:
1 1
0
0
0
0
0
0
195 + 105 = 2 ∙ (195 + 105 ) ∙ (195 − 105 )
2 2
1 1
0
0
= 2 ∙ (300 ) ∙ (90 )
2 2
0
0
= 2 ∙ 150 ∙ 45
1 1
= 2 (− √3) ( √2)
2 2
1
= − √6
2

Contoh 3:
0
0
Hitunglah nilai dari 105 − 15 .
Penyelesaian:
1 1
0
0
0
0
0
0
105 − 15 = 2 ∙ (105 + 15 ) ∙ (105 − 15 )
2 2
1 1
0
0
= 2 ∙ (120 ) ∙ (90 )
2 2
0
0
= 2 ∙ 60 ∙ 45
1 1
= 2 ( ) ( √2)
2 2
1
= √2
2

Contoh 4:
− 2 + 3
Sederhanakan bentuk .
− 2 + 3
Penyelesaian:
− 2 + 3

− 2 + 3
+ 3 − 2
=
+ 3 − 2
2 2 (− ) − 2
=
2 2 (− ) − 2
2 ( (− ) − 1)
=
2 ( (− ) − 1)
= 2

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